Python TQC考題202_倍數判斷, x%3==0(%求餘數) x%5!=0 (!= 不等於)

#Python TQC考題202_倍數判斷

 

x=eval(input())
if x%3==0 and x%5==0:
    print(“{} is a multiple of 3 and 5.”.format(x))

#沒有要設定格式, { }中的:可加可不加

#加了:也可正常執行

 

elif x%3==0 and x%5!=0:
    print(“{} is a multiple of 3.”.format(x))

elif x%3!=0 and x%5==0:
    print(“{} is a multiple of 5.”.format(x))

else:
    print(“{} is not a multiple of 3 and 5.”.format(x))

 

# { }中有加:仍可正常執行:

 

 

# n%3 == 0,後面再加 and n%5 != 0

#看似比較嚴謹,但沒加沒出錯