參考前篇: 如何串接Meta API ?
list 要從生成的json與jieba斷詞套件取得
以及: 全文件詞頻(term frequency,簡稱TF)計算
code:
# -*- coding: utf-8 -*-
"""
Created on Mon Jan 15 06:30:23 2024
@author: SavingKing
"""
import os
import json
import jieba
folder = r"D:\Python code\240107_爬蟲"
fname = "my_lis_msg_backup.json"
fpath = os.path.join(folder,fname)
#'D:\\Python code\\240107_爬蟲\\my_lis_msg.json'
with open(fpath,"r",encoding="UTF-8") as f:
    dic = json.load(f)
k0 = list(dic.keys())[0]
lis = dic[k0]
strr = "\n".join(lis)
lis_jieba = jieba.lcut(strr)
leng = len( lis_jieba )
dic_term_freq = {}
for term in lis_jieba:
    if term in dic_term_freq:
        dic_term_freq[term] += 1/leng
    else:
        dic_term_freq[term] = 1/leng
print(dic_term_freq)輸出結果:

推薦hahow線上學習python: https://igrape.net/30afN
出現最多的是那些詞?
詞頻多少?
# -*- coding: utf-8 -*-
"""
Created on Mon Jan 15 06:30:23 2024
@author: SavingKing
"""
import os
import json
import jieba
folder = r"D:\Python code\240107_爬蟲"
fname = "my_lis_msg_backup.json"
fpath = os.path.join(folder,fname)
#'D:\\Python code\\240107_爬蟲\\my_lis_msg.json'
with open(fpath,"r",encoding="UTF-8") as f:
    dic = json.load(f)
k0 = list(dic.keys())[0]
lis = dic[k0]
strr = "\n".join(lis)
lis_jieba = jieba.lcut(strr)
while "\n" in lis_jieba:
    lis_jieba.remove("\n")
    
while ',' in lis_jieba:
    lis_jieba.remove(',')
while '。' in lis_jieba:
    lis_jieba.remove('。')
    
leng = len( lis_jieba )
dic_term_freq = {}
for term in lis_jieba:
    if term in dic_term_freq:
        dic_term_freq[term] += 1/leng
    else:
        dic_term_freq[term] = 1/leng
print(dic_term_freq)
#出現最多的是那些詞? 詞頻多少?
max_count = max(dic_term_freq.values())
lis_max_count=[]
for k in dic_term_freq:
    if dic_term_freq[k] == max_count:
        lis_max_count.append(k)
print("max_count:",max_count)
print("lis_max_count:",lis_max_count)輸出結果:

詞頻最高的是”\n”
去掉”\n”後
變成逗點
去掉逗點後
變成句點
需要使用IDF(Inverse Document Frequency)
濾掉詞頻高
但是卻不重要的詞
簡單點的話,
則可以挑選長度>=2的詞
推薦hahow線上學習python: https://igrape.net/30afN
使用list.count(str)
取代以下語法得到的dic_TF
for term in lis_jieba:
    if term in dic_term_freq:
        dic_term_freq[term] += 1/leng
    else:
        dic_term_freq[term] = 1/lenglist.count(str)
code:
# -*- coding: utf-8 -*-
"""
Created on Sun Jan 21 13:09:21 2024
@author: SavingKing
"""
import os
import json
import jieba
dirname = r"D:\Python code\240107_爬蟲"
basename= "my_lis_msg_backup.json"
json_path = os.path.join(dirname,basename)
with open(json_path,"r",encoding="UTF-8") as f:
    dic = json.load(f)
    
lis = dic['my lis_msg']
lis2D=[]
for ele in lis:
    lis2D.append(jieba.lcut(ele))
lis2D_flatten = []
for ele in lis2D:
    lis2D_flatten.extend(ele)
#只要長度大於2的詞
lis2D_flatten_2 = []
for ele in lis2D_flatten:
    if len(ele) >=2:
        lis2D_flatten_2.append(ele)
dic_TF ={}
for word in set(lis2D_flatten_2):
    tf = lis2D_flatten_2.count(word)
    dic_TF.update({word:tf})
    
lis_sort = sorted(dic_TF.items(),
                  key=lambda tup:tup[1],
                  reverse=True )
for ele in lis_sort:
    if ele[1]>7:
        print(ele[0],ele[1])輸出結果

推薦hahow線上學習python: https://igrape.net/30afN












 
																			 
																			 
																			
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