Python撲克牌的4種花色,撲克牌洗牌

#Python撲克牌的4種花色

spade = [0]*13 ; heart = [0]*13
diamond = [0]*13 ; club = [0]*13
for i in range(13):
spade[i] = “spade %d”%(i+1)
heart[i] = “hrart %d”%(i+1)
diamond[i] = “diamond %d”%(i+1)
club[i] = “club %d”%(i+1)
print(spade) ; print(heart)
print(diamond) ; print(club)

#撲克牌洗牌

#少寫了防重複邏輯

#但多寫防重複邏輯,

#發的牌又會少於52張,

#每次不一定發幾張

spade = [0]*13 ; heart = [0]*13
diamond = [0]*13 ; club = [0]*13
for i in range(13):
spade[i] = “spade %d”%(i+1)
heart[i] = “hrart %d”%(i+1)
diamond[i] = “diamond %d”%(i+1)
club[i] = “club %d”%(i+1)
a=[] ; b=[] ; c=[] ; d=[]
cards = [spade,diamond,heart,club]
#print(cards[3][12])
L=[]
import random
for r in range(4):
for c in range(13):
suit = random.randint(0,3)
pts = random.randint(0,12)
L.append(cards[suit][pts])
a = L[0:13]
b = L[13:26]
c = L[26:39]
d = L[39:52]

print(a) ; print(b) ; print(c) ; print(d)
print(len(a)) ; print(len(b))
print(len(c)) ; print(len(d))
#print(L)
#print(len(L))

#spyder輸出結果:

#第二次洗牌:

“””

a = L[0:13]
b = L[13:26]
c = L[26:39]
d = L[39:52]

把以上移出雙層迴圈之外,

也可以運作,邏輯上也好理解:

“””

“””

創出了L為長度52,元素為花色+點數的list

前篇的撲克牌洗牌

已經可以不重複亂數發出13張*4

使用迴圈應可以將數字替換為

L中的花色+數字

for i in range(1:53):

if      i in a :  a[ a.index(i) ] = L[(i-1)]

elif  i in b :  b[ b.index(i) ] = L[(i-1)]

elif  i in c :  c[ c.index(i) ] = L[(i-1)]

elif  i in d :  d[ d.index(i) ] = L[(i-1)]

“””

#不同方式創出長度52,

#元素為花色+點數的list

#不用多一個2D list中介

“””以下有錯誤:

File “C:\Users\USER\OneDrive\桌面\untitled0.py”, line 20, in <module>
elif cards[suit][pts] not in c:

TypeError: argument of type ‘int’ is not iterable

邏輯也有誤,第一次迴圈,創出來的第一個元素,

一定同時不在a,b,c,d,那要歸給誰?

其實錯誤在 for c in range(13)

c 跟list c重複了

但此邏輯依然不行,

a,b,c,d會發不等數目的牌

“””

spade = [0]*13 ; heart = [0]*13
diamond = [0]*13 ; club = [0]*13
for i in range(13):
spade[i] = “spade %d”%(i+1)
heart[i] = “hrart %d”%(i+1)
diamond[i] = “diamond %d”%(i+1)
club[i] = “club %d”%(i+1)
a=[] ; b=[] ; c=[] ; d=[]
cards = [spade,diamond,heart,club]
print(cards[3][12])
import random
for r in range(4):
for c in range(13):
suit = random.randint(0,3)
pts = random.randint(0,12)
if cards[suit][pts] not in a:
a.append( cards[suit][pts] )
elif cards[suit][pts] not in b:
b.append( cards[suit][pts] )
elif cards[suit][pts] not in c:
c.append( cards[suit][pts] )
elif cards[suit][pts] not in d:
d.append( cards[suit][pts] )
print(a) ; print(b) ; print(c) ; print(d)

#可以改成如下:

#輸出結果:

#最終版本:

輸出結果:

#意思一樣,但多寫了一次迴圈: